Practicing Success
If $A=\begin{bmatrix}2 & 0 & 0 \\ 0 & 2 & 0\\ 0& 0 & 2\end{bmatrix}$ then $A^5$ is : |
$5A$ $16A$ $32A$ $64A$ |
$16A$ |
The correct answer is Option (2) → $16A$ $A=\begin{bmatrix}2 & 0 & 0 \\ 0 & 2 & 0\\ 0& 0 & 2\end{bmatrix}=2I$ $A^5=2^5I=2^4(2I)$ $=2^4A$ $=16A$ |