If a female is a carrier for colour blindness, marries a male which i…

The correct answer is Option (2) - 50% sons diseased  and 50% daughters (carrier).

• Color blindness is a sex-linked recessive disorder, meaning the gene responsible is located on the X chromosome.
• A female carrier has one normal X chromosome and one X chromosome with the color blindness gene (X^CX).
• A normal male has one X chromosome and one Y chromosome (XY).

When a carrier female (X^CX) marries a normal male (XY), the possible combinations for their children are:

1. For sons:
• Sons inherit the Y chromosome from their father and one X chromosome from their mother.
• There’s a 50% chance a son will inherit the X^C (color-blind gene) and become color-blind (X^CY).
• There’s a 50% chance a son will inherit the normal X and be normal (XY).
2. For daughters:
• Daughters inherit one X chromosome from each parent.
• There’s a 50% chance a daughter will inherit the normal X from both parents, making her normal (XX).
• There’s a 50% chance a daughter will inherit the X^C from the mother and the normal X from the father, making her a carrier (X^CX), but not color-blind.

Therefore, 50% of the sons will be diseased, and 50% of the daughters will be carriers.