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The domain of the function $\cos^{-1}(2x - 1)$ is |
$[0, 1]$ $[-1, 1]$ $(-1, 1)$ $[0, \pi]$ |
$[0, 1]$ |
The correct answer is Option (1) → $[0, 1]$ ## We have, $f(x) = \cos^{-1}(2x - 1)$ $∵ -1 \le 2x - 1 \le 1 \Rightarrow 0 \le 2x \le 2$ $\Rightarrow 0 \le x \le 1$ $∴x \in [0, 1]$ |
