Practicing Success
If $A (2a+3b, a +6b)$ and $B (3a + 4b, 2a + 5b)$ are two points, then distance between the points A and B is: |
\(\sqrt { 2(a² + b²) }\) $\sqrt{2}(a^2-b^2)$ $2ab$ $\sqrt{2(a^2-b^2)}$ |
\(\sqrt { 2(a² + b²) }\) |
Distance between two points A(x1 , y1) and B(x2 , Y2 ) = \(\sqrt { (x2 - x1 )² + (y2 - y1)² }\) Now, Distance between two points A (2a + 3b , a + 6b ) and B ( 3a + 4b , 2a + 5b ) = \(\sqrt { ( (3a+4b) - (2a+3b) )² + ( (2a+5b) - (a+6b) )² }\) = \(\sqrt { ( a + b) )² + ( a - b )² }\) = \(\sqrt { 2(a² + b²) }\)
B(3a+4b,2a+5b) |