The electric potential at a point P due to a point charge of \( 9\,\mu\mathrm{C} \) located 10 cm away from point P is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( 8.1\times10^{5}\,\mathrm{V} \)
The electric potential of a point charge at a distance \( r \) is \( V = kq/r \).
\( q = 9\,\mu\mathrm{C} = 9\times10^{-6}\,\mathrm{C} \)
\( r = 10\,\mathrm{cm} = 0.1\,\mathrm{m} \)
\( \displaystyle V = \frac{9\times10^{9} \times 9\times10^{-6}}{0.1} = \frac{8.1\times10^{4}}{0.1} = 8.1\times10^{5}\,\mathrm{V} \)
Note: NTA picked this question from an NCERT (2026-27) example and changed the figures. Do not ignore NCERT while practising numericals.
NCERT (2026-27):
Potential Due to a Point Charge – …
