The value of (2 + tan^2 θ + cot^2 θ)/(sec θ cosec θ ) is?

Use θ = 45°

\(\frac{2 + tan^2 θ + cot^2 θ}{sec θ\;cosec θ }\) = \(\frac{2 + tan^2 45° + cot^2 45°}{sec 45°\;cosec 45° }\)

   = \(\frac{2 + 1 + 1}{\sqrt {2}.\sqrt {2}}\) = \(\frac{4}{2}\) = 2

satisfied by option c) sec θ cosec  θ