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The value of \(\frac{2 + tan^2 θ + cot^2 θ}{sec θ\;cosec θ }\) is? |
cot θ cos θ sin θ secθ cosec θ sin θ + cos θ |
secθ cosec θ |
Use θ = 45° \(\frac{2 + tan^2 θ + cot^2 θ}{sec θ\;cosec θ }\) = \(\frac{2 + tan^2 45° + cot^2 45°}{sec 45°\;cosec 45° }\) = \(\frac{2 + 1 + 1}{\sqrt {2}.\sqrt {2}}\) = \(\frac{4}{2}\) = 2 satisfied by option c) sec θ cosec θ |
