A wire of length L metre carrying a current I ampere is bent in the form of a circle. Its magnitude of magnetic moment will be

$IL^2/4π$

The correct answer is Option 4: $IL^2/4π$

$\text{Length of loop } L = 2\pi r$

$\Rightarrow r = \frac{L}{2\pi}$

$\text{magnetic Moment } M = IA = I\pi r^2 = I \pi \frac{L^2}{4\pi^2}$

$ M =\frac{IL^2}{4\pi}$