CUET Preparation Today
A wire of length L metre carrying a current I ampere is bent in the form of a circle. Its magnitude of magnetic moment will be |
$IL/4p$ $I^2L^2/4p$ $I^2L/8p$ $IL^2/4p$ |
$IL^2/4p$ |
$\text{Length of loop } L = 2\pi r$ $\Rightarrow r = \frac{L}{2\pi}$ $\text{magnetic Moment } M = IA = I\pi r^2 = I \pi \frac{L^2}{4\pi^2}$ $ M =\frac{IL^2}{4\pi}$ |
