Match List-I with List-II.

List-I	List-II

Choose the correct answer from the options given below:

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

The correct answer is (3) (A)-(II), (B)-(III), (C)-(IV), (D)-(I).

(A) When aniline reacts with bromine water it undergoes bromination. Due to this a white precipitate of \(2,4,6−tribromoaniline\) forms causing the discoloration of bromine water.

This is an electrophilic substitution reaction of bromine on aniline, because the \(NH_2\) group in aniline activates the benzene ring due to the presence of lone pair of electrons on nitrogen atom of \(NH_2\) group. It shifts its electron density toward the benzene ring making it susceptible for the electrophilic attack of bromine \((Br^+)\) at ortho and para position.

(B) (C)

(D)