Match List-I with List-II.
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Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is option 3. (A)-(II), (B)-(III), (C)-(IV), (D)-(I).
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(A) When aniline reacts with bromine water it undergoes bromination. Due to this a white precipitate of \(2,4,6−tribromoaniline\) forms causing the discoloration of bromine water.
This is an electrophilic substitution reaction of bromine on aniline, because the \(NH_2\) group in aniline activates the benzene ring due to the presence of lone pair of electrons on nitrogen atom of \(NH_2\) group. It shifts its electron density toward the benzene ring making it susceptible for the electrophilic attack of bromine \((Br^+)\) at ortho and para position.
(B)
(C)
(D)
