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If 4x - 3y = 12 and xy = 5, then find the value of $\frac{16 x^2+9 y^2}{8}$. |
33 18 3 44 |
33 |
We know that, (a - b)2 = a2 + b2 - 2ab 4x - 3y = 12 = (4x - 3y)2 = 122 = 16x2 + 9y2 - 24xy = 144 = 16x2 + 9y2 - 24 × 5 = 144 = 16x2 + 9y2 - 120 = 144 = 16x2 + 9y2 = 264 $\frac{16 x^2+9 y^2}{8}$ = $\frac{264}{8}$ = 33 |
