If, for a non-zero x, $5x^2+7x+5= 0$, then the value of $x^3 +\frac{1}{x^3}$ is:
Answer & explanation
Correct answer: option 4
$5x^2+7x+5= 0$
Dividing by 5x on both sides.
If x + \(\frac{1}{x}\) = n
then, $x^3 +\frac{1}{x^3}$ = n3 - 3n
x + \(\frac{1}{x}\) = \(\frac{7}{5}\)
$x^3 +\frac{1}{x^3}$ = (\(\frac{7}{5}\))3 - 3 × \(\frac{7}{5}\) = -$\frac{182}{125}$