CUET Preparation Today
Simplify $\frac{\sqrt{81}+\sqrt[3]{64}}{\sqrt{3^3+4^2+\sqrt[3]{216}}}$ |
$\frac{17}{7}$ $\frac{13}{7}$ $\frac{12}{13}$ $\frac{13}{17}$ |
$\frac{13}{7}$ |
$\frac{\sqrt{81}+\sqrt[3]{64}}{\sqrt{3^3+4^2+\sqrt[3]{216}}}$ = \(\frac{9 + 4}{ \sqrt {27 + 16 + 6} }\) = \(\frac{13}{ \sqrt {49}}\) = $\frac{13}{7}$ |
