Simplify frac√81+sqrt[3]64sqrt3^3+4^2+sqrt[3]216

$\frac{\sqrt{81}+\sqrt[3]{64}}{\sqrt{3^3+4^2+\sqrt[3]{216}}}$

= \(\frac{9 + 4}{ \sqrt {27 + 16 + 6} }\)

= \(\frac{13}{ \sqrt {49}}\)

= $\frac{13}{7}$