A is twice as good a workman as B, and together they finish a piece of work in 13 days. In how many days will A alone finish the work? |
41 39 $19 \frac{1}{2}$ $9 \frac{1}{4}$ |
$19 \frac{1}{2}$ |
Given, A is twice as good a workman as B, Therefore A : B = 2 : 1 (Efficiency) ⇒ A + B worked for 13 days = (2 + 1) x 13 = 39 units ..(Efficiency × Days = Total work) ⇒ Time required for A to complete total work alone = \(\frac{39}{2}\) = \( {19 }_{ 2}^{ 1} \) days. ..(\(\frac{Work}{Efficiency}\) = Time) |