A is twice as good a workman as B, and together they finish a piece of work in 13 days. In how many days will A alone finish the work?
Answer & explanation
Correct answer: option 3
Given,
A is twice as good a workman as B,
Therefore A : B = 2 : 1 (Efficiency)
⇒ A + B worked for 13 days = (2 + 1) x 13 = 39 units ..(Efficiency × Days = Total work)
⇒ Time required for A to complete total work alone = \(\frac{39}{2}\) = \( {19 }_{ 2}^{ 1} \) days. ..(\(\frac{Work}{Efficiency}\) = Time)