Find the value of tan 3θ if sec 3θ= cosec (4θ-15°).
Answer & explanation
Correct answer: option 4
Given :-
sec 3θ= cosec (4θ-15°)
If secA = cosecB then A + B = 90º
So , 3θ + 4θ - 15° = 90°
7θ = 105°
θ = 15°
Now , tan 3θ = tan 45° = 1
Find the value of tan 3θ if sec 3θ= cosec (4θ-15°).
Correct answer: option 4
Given :-
sec 3θ= cosec (4θ-15°)
If secA = cosecB then A + B = 90º
So , 3θ + 4θ - 15° = 90°
7θ = 105°
θ = 15°
Now , tan 3θ = tan 45° = 1