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CUET
General Test
Quantitative Reasoning
Trigonometry
Find the value of tan 3θ if sec 3θ= cosec (4θ-15°).
$\frac{1}{\sqrt{3}}$
$\sqrt{3}$
-1
1
Given :-
sec 3θ= cosec (4θ-15°)
If secA = cosecB then A + B = 90º
So , 3θ + 4θ - 15° = 90°
7θ = 105°
θ = 15°
Now , tan 3θ = tan 45° = 1
