Practicing Success
Practicing Success
CUET Preparation Today
|
a b c d |
c |
Acceleration of electron is $ a = \frac{v^2}{r} $ Since $mvr = \frac{h}{2\pi} \Rightarrow v = \frac{h}{2\pi mr}$ $ a = \frac{v^2}{r} = \frac{h^2}{4\pi^2 m^2r^3}$ |
