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The maximum value of a LPP $z = 3x + 4y$ subject to the constraints: $x + y ≤6, x≥0,y≥0$ is: |
24 30 36 28 |
24 |
The correct answer is Option (1) → 24 $\text{Maximize } z=3x+4y \text{ subject to } x+y\le 6,\; x\ge 0,\; y\ge 0.$ Corner points: $(0,0),\ (6,0),\ (0,6)$. $z(0,0)=0,\quad z(6,0)=18,\quad z(0,6)=24.$ Maximum value = 24 at $(0,6)$.
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