The maximum value of a LPP \(z = 3x + 4y\) subject to the constraints: \(x + y \le 6,\ x \ge 0,\ y \ge 0\) is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 24
The feasible region is the triangle bounded by the axes and the line \(x + y = 6\). Its corner points are (0, 0), (6, 0) and (0, 6). Values of \(z = 3x + 4y\):
\((0, 0):\ z = 0\)
\((6, 0):\ z = 18\)
\((0, 6):\ z = 24\)
The maximum value is 24, at (0, 6).