The antiderivative of \(\left(\sqrt{x}+\frac{1}{\sqrt{x}}\right)\) equals
Answer & explanation
Correct answer: option 3
\(\int \sqrt{x}dx=\frac{2}{3}x^{\frac{3}{2}},\int \frac{1}{\sqrt{x}}dx=2x^{\frac{1}{2}}\)
The antiderivative of \(\left(\sqrt{x}+\frac{1}{\sqrt{x}}\right)\) equals
Correct answer: option 3
\(\int \sqrt{x}dx=\frac{2}{3}x^{\frac{3}{2}},\int \frac{1}{\sqrt{x}}dx=2x^{\frac{1}{2}}\)