If $a + b + c = 5$ and $a^3 + b^3 + c^3 - 3abc = 185$, then the value of $ab + bc + ca$ lies between :
Answer & explanation
Correct answer: option 1
If $a + b + c = 5$
$a^3 + b^3 + c^3 - 3abc = 185$
then the value of $ab + bc + ca$ lies between= ?
If the number of equations are less than the number of variables then we can put the extra variables according to our choice =
So here two equations given and three variables are present so put c = 0
If $a + b = 5$
$a^3 + b^3 = 185$
then the value of $ab$ = ?
We know that,
(a + b)3 = a3 + b3 + 3ab(a+b)
(5)3 = 185 + 3ab(5)
125 - 185 = 15ab
15ab = -60
ab = -4
So, the value of $ab + bc + ca$ lies between -7 and -3