Practicing Success
Simplify the following expression : $\frac{1-sinA}{cosA}+\frac{cosA}{1-sinA}$ |
2 sinA 2cosA 2secA 2tanA |
2secA |
$\frac{1-sinA}{cosA}+\frac{cosA}{1-sinA}$ = \(\frac{( 1 -sinA)² + cos²A }{cosA(1-sinA)}\) = \(\frac{( 1 + sin²A - 2sinA) + cos²A }{cosA(1-sinA)}\) { using , sin²A + cos²A = 1 } = \(\frac{( 1 + 1 - 2sinA) }{cosA(1-sinA)}\) = \(\frac{2( 1 - sinA) }{cosA(1-sinA)}\) = \(\frac{2 }{cosA}\) = 2secA |