If the optimal value of the objective function $z = px + y$ of an L.P.P occurs at two corner points (2, 11) and (4, 5) of its bounded feasible region, then its optimal value is |
15 16 18 17 |
17 |
The correct answer is Option (4) → 17 Given:
Since the optimal value is the same at both points, we equate the values of $z$ at these points: $z = p(2) + 11 = p(4) + 5$ $\Rightarrow 2p + 11 = 4p + 5$ $\Rightarrow 6 = 2p \Rightarrow p = 3$ Now substitute $p = 3$ into the objective function to find the optimal value: $z = 3x + y$ At point $(2, 11)$: $z = 3(2) + 11 = 6 + 11 = {17}$ |