Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

Options:

a

b

c

d

Correct Answer:

d

Explanation:

$ P = VI$

$ I = \frac{P}{V} = \frac{1}{6}$

$R = \frac{V}{I} = 360\Omega$

$ \text{Impedance required is } Z = \frac{100}{1/6} = 600 \Omega$

$ X_L = \sqrt {z^2 - R^2} = 480\Omega$

$ L = \frac{X_L}{\omega} = \frac{480}{120\pi}= 1.28 H$