A 60 volt-10 watt bulb is operated at 100 volt-60 Hz a.c. The inductance required is
Answer & explanation
Correct answer: option 4
$ P = VI$
$ I = \frac{P}{V} = \frac{1}{6}$
$R = \frac{V}{I} = 360\Omega$
$ \text{Impedance required is } Z = \frac{100}{1/6} = 600 \Omega$
$ X_L = \sqrt {z^2 - R^2} = 480\Omega$
$ L = \frac{X_L}{\omega} = \frac{480}{120\pi}= 1.28 H$