Practicing Success
A converging beam of rays is incident on a concave lens. After passing through the lens, the rays converge at a distance of 15 cm from the lens on the other side. If the lens is removed, the converging point of rays decreases by 5 cm. The focal length of lens is: |
-10 cm -20 cm -30 cm -5 cm |
-30 cm |
In the absence of concave lens the rays are focussed at 10cm . $\Rightarrow u = +10 cm , V = 15 cm$ $\Rightarrow \frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{15} - \frac{1}{10} = \frac{2-3}{30} = \frac{-1}{30}$ $ \Rightarrow f = -30cm$
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