A pole of height 94 m is broken in such a way that its top part is not completely separated but falls to ground and make at an of 30° with the ground. Find the height at which pole is broken.
Answer & explanation
Correct answer: option 1
AC = 94 m
Let, BC = x
A'B = 94 - x
sin 30° = \(\frac{BC}{A'B}\) ⇒ \(\frac{1}{2}\) = \(\frac{x}{94 - x}\)
⇒ 94 - x = 2x
⇒ x = 31.33 m
Therefore, post broke at the height of 31.33 m