A pole of height 94 m is broken in such a way that its top part is not completely separated but falls to ground and make at an of 30° with the ground. Find the height at which pole is broken.

31.33 m

AC = 94 m

Let, BC = x

A'B = 94 - x

sin 30° = \(\frac{BC}{A'B}\) ⇒ \(\frac{1}{2}\) = \(\frac{x}{94 - x}\)

⇒ 94 - x = 2x

⇒ x = 31.33 m 

Therefore, post broke at the height of 31.33 m