Practicing Success
Practicing Success
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If $f'(x)=(x-a)^{2 n}(x-b)^{2 m+1}$ where m, $n \in N$, then |
x = a is a point of minimum x = a is a point of maximum x = a is not a point of maximum or minimum None of these |
x = a is not a point of maximum or minimum |
f'(x) = (x – a)2n (x – b)2m + 1 ∴ f'(x) = 0 ⇒ x = a, b f'(x) does not change sign while passing through x = a. Hence 'a' is neither a point of maximum nor a point of minimum. |
