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If $y=7 \sqrt{x}+3 e^x$, then $\frac{dy}{dx}$ is: |
$\frac{7}{2 \sqrt{x}}+3 e^x$ $\frac{-7}{4} x^{-\frac{3}{2}}$ $\frac{-7}{4} x^{\frac{3}{2}}$ $\frac{7}{2} x^{\frac{-3}{2}}+e^x$ |
$\frac{7}{2 \sqrt{x}}+3 e^x$ |
The correct answer is Option (1) - $\frac{7}{2 \sqrt{x}}+3 e^x$ $y=7 \sqrt{x}+3 e^x$ $⇒\frac{dy}{dx}=7×\frac{1}{2\sqrt{x}}+3e^x$ $=\frac{7}{2 \sqrt{x}}+3 e^x$ |
