Practicing Success
The value of b for which the function $f(x) = sin x - bx + C, $ where b and c are constants is decreasing for $x \in R$ is given by |
$b < 1$ $b ≥0$ $b> 1$ $b ≤ 1$ |
$b> 1$ |
The correct answer is Option (3) → $b> 1$ $f(x) = \sin x - bx + C$ $f'(x)=\cos x-b$ $max(\cos x)=1$ so for $f'(x)$ to be decreasing $b>1⇒f'(x)<0$ always |