Find the values of x for the given equation $3x^2 +5x - 2 = 0 $

-3 and -2 3 and $-\frac{1}{2}$ 2 and -3 -2 and $\frac{1}{3}$

-2 and $\frac{1}{3}$

3x2 + 5x - 2 = 0 = 3x2 + 5x - 2 = 3x2 + 6x - x - 2 = 3x(x + 2) -1(x + 2) = (3x - 1)(x + 2) = 3x - 1 = 0 so, x = \(\frac{1}{3}\) = x + 2 = 0 so x = -2