CUET Preparation Today
| If \(P(A \cap B)=\frac{1}{2}, P(\bar{A}\cap \bar{B})=\frac{1}{3},P(A)=x\) and \(P(B)=2x\), then the value of \(x\) is |
\(\frac{1}{2}\) \(\frac{4}{9}\) \(\frac{3}{2}\) \(\frac{7}{18}\) |
| \(\frac{7}{18}\) |
| \(P(A\cap B)=P(A)+P(B)-P(A \cap B)\) |
