If $\sin 44^{\circ}=x$, then the value of $\tan 46^{\circ}$ will be:

$\frac{\sqrt{1-x^2}}{x}$

$\sin 44^{\circ}=x$ = $\sin 90-44^{\circ}$ = $\cos 46^{\circ}=x$

Also, $ sin^2 A + cos^2 A = 1$

$ sin^2 A + x^2 = 1$

$\sin 46^{\circ}$ = $sqrt (1- x^2)$

Tan 46º = $\frac{\sqrt{1-x^2}}{x}$

The correct answer is Option (3) → $\frac{\sqrt{1-x^2}}{x}$