If x + y + z = 0, then what is the value of $ \frac{x^2}{(yz)}+\frac{y^2}{(xz)}+\frac{z^2}{(xy)}$ ?
Answer & explanation
Correct answer: option 4
If x + y + z = 0
then x3 + y3 + z3 = 3xyz (always)
Find, $ \frac{x^2}{(yz)}+\frac{y^2}{(xz)}+\frac{z^2}{(xy)}$ = ?
$ \frac{x^2}{(yz)}+\frac{y^2}{(xz)}+\frac{z^2}{(xy)}$ = \(\frac{x^3 + y^3 + x^3}{xyz}\)
= \(\frac{3xyz }{xyz}\) = 3