If x + y + z = 0, then what is the value of $ \frac{x^2}{(yz)}+\frac{y^2}{(xz)}+\frac{z^2}{(xy)}$ ?

3

If x + y + z = 0

then x³ + y³ + z³ = 3xyz (always)

Find, $ \frac{x^2}{(yz)}+\frac{y^2}{(xz)}+\frac{z^2}{(xy)}$ = ?

 $ \frac{x^2}{(yz)}+\frac{y^2}{(xz)}+\frac{z^2}{(xy)}$ = \(\frac{x^3 + y^3 + x^3}{xyz}\)

= \(\frac{3xyz }{xyz}\) = 3