Let f(x) = Maximum {sin, cos} ∀ x

CUET Preparation Today

Start Free Mocks

Home Questions ME62SD36YP

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

Let f(x) = Maximum {sin, cos} ∀ x ∈ R. minimum value of f (x) is:

Options:

$(1-\sqrt{2})$

-1

$(1-\frac{1}{\sqrt{2}})$

$\frac{-1}{\sqrt{2}}$

Correct Answer:

$\frac{-1}{\sqrt{2}}$

Explanation:

Draw graph

Points of change are when sin x = cos x ⇒ tan x = 1

At the point, minimum value of sin x = cos x = $\frac{-1}{\sqrt{2}}$