If sin $x = \frac{12}{37}$, then what is the value of tan x ?

$\frac{35}{37}$ $\frac{12}{35}$ $\frac{37}{12}$ $\frac{35}{12}$

$\frac{12}{35}$

sinx =  \(\frac{12}{37}\) { sinx =  \(\frac{P }{H}\) } P² + B² = H² 12² + B² = 37² B = 35 Now,  tanx =  \(\frac{P }{B}\) = \(\frac{ 12 }{35}\)