Practicing Success
For a first-order reaction, what is the ratio between the time taken to complete three fourth of the reaction and the time taken to complete half of the reaction? |
2:1 3:1 2:3 3:2 |
2:1 |
The correct answer is option 1. 2:1. For a first order reaction, t = \(\frac{2.303}{k}\)log\(\frac{a}{a-x}\) For \(\frac{3}{4}\) of the reaction to occur, t = t3/4, (a - x) = a - \(\frac{3a}{4}\) = \(\frac{a}{4}\) ∴ t3/4 = \(\frac{2.303}{k}\)log4 For half of a reaction to occur, t = t1/2, (a - x) = a - \(\frac{a}{2}\) = \(\frac{a}{2}\) ∴ t1/2 = \(\frac{2.303}{k}\)log\(\frac{a}{\frac{a}{2}}\) = \(\frac{2.303}{k}\)log2 Hence, \(\frac{t_{3/4}}{t_{1/4}}\) = \(\frac{log4}{log2}\) = \(\frac{0.06021}{0.3010}\) = 2 |