The projection of a vector on the three coordinate axes are \(6,-3,2\) respectively then the direction cosine of the vector are

\(6,-3,2\) \(\frac{6}{5},-\frac{3}{5},\frac{2}{5}\) \(\frac{6}{7},\frac{-3}{7},\frac{2}{7}\) \(\frac{-6}{7},\frac{3}{7},\frac{-2}{7}\)

\(\frac{6}{7},\frac{-3}{7},\frac{2}{7}\)

divide each by \(\sqrt{6^2+(-3)^2+2^2}\)