Dichlorocarbene is obtained by the \(\alpha\)-elimination of

CHCl₃

The correct answer is option 1. CHCl₃

\(\alpha\)-elimination (eliminations in which both the proton and the leaving group are located on the same atom) follow a mechanism akin to an \(E_{1_{cB}}\) β-elimination. A strong base removes an acidic proton adjacent to an electron-withdrawing group to give a carbanion. Loss of a leaving group from the carbanion creates a carbene. One of the best-known elimination reactions occurs when chloroform is treated with base, forming a dichlorocarbene.