Practicing Success
Practicing Success
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Solve the following inequations $\frac{2x+4}{x-1}≥0$ |
(1, 3] (1, 2) [1, 2) (2, 3] |
(1, 3] |
We have $\frac{2x+4}{x-1}≥0⇒\frac{2x+4}{x-1}-5≥0$ $⇒\frac{2x+4-5(x-1)}{x-1}≥0⇒\frac{2x+4-5x+5}{x-1}≥0$ $\frac{-3x+9}{x-1}≥0$ [Multiplying both sides by -1] $\frac{3x-9}{x-1}≤0⇒\frac{3(x-3)}{x-1}≤0$ [Dividing both sides by 3] $\frac{x-3}{x-1}≤0⇒1<x≤3⇒x∈(1,3]$ |
