Practicing Success
Practicing Success
CUET Preparation Today
If $A=\left[\begin{array}{ll}4 & 1 \\ 5 & 8\end{array}\right]$ and $A+A^{T}=\left[\begin{array}{ll}8 & a \\ 6 & b\end{array}\right]$ is a symmetric matrix, then a and b are: |
$a=6, b=16$ $a=6, b=6$ $a=16, b=8$ $a=16, b=16$ |
$a=6, b=16$ |
The correct answer is Option (1) → $a=6, b=16$ |
