If the volume of a sphere is 179$\frac{2}{3}$ m³, what is its surface area ?

154 m²

We know that,

Volume of a sphere = \(\frac{4}{3}\) πr³

Surface area of a sphere = 4πr²

\(\frac{4}{3}\) πr³ = 179$\frac{2}{3}$

\(\frac{4}{3}\) πr³ = \(\frac{539}{3}\)

= 4πr³ = 539

= 4 × \(\frac{22}{7}\) × r³ = 539

= 4 × \(\frac{2}{7}\) × r³ = 49

= r³ = 49×\(\frac{7}{8}\) 

= r = 3.5

Surface area = 4 × \(\frac{22}{7}\)  × 3.5² = 154 m²