Molarity of solution containing 8 g of NaOH in 200 mL solution is: (Molar mass of NaOH = 40 g mol-1)

25 M 1 M 0.001 M \(\frac{1}{25}\) M

1 M

No. of moles of NaOH = \(\frac{8}{40}\) = \(\frac{1}{5}\) = 0.2 Volume of solution = 200 mL Molarity, M = \(\frac{\text{No. of moles of solute}}{\text{Volume of solution (in mL)}}\) x 1000 M = \(\frac{0.2}{200}\) x 1000 = 1 M