Molarity of solution containing 8 g of NaOH in 200 mL solution is:
(Molar mass of NaOH = 40 g mol-1)
Answer & explanation
Correct answer: option 2
No. of moles of NaOH = \(\frac{8}{40}\) = \(\frac{1}{5}\) = 0.2
Volume of solution = 200 mL
Molarity, M = \(\frac{\text{No. of moles of solute}}{\text{Volume of solution (in mL)}}\) x 1000
M = \(\frac{0.2}{200}\) x 1000 = 1 M