Practicing Success
Let us define the length of a vector $a\hat i +b\hat j+c\hat k$ as $|a|+|b|+|c|$. This definition coincides with the usual definition of length of a vector $a\hat i +b\hat j+c\hat k$ iff |
$a=b=c=0$ any two of a, b and c are zero any one of a, b and c is zero $a+b+c=0$ |
any two of a, b and c are zero |
We have, $|a\hat i +b\hat j + c\hat k|=|a|+|b|+|c|$ $⇒\sqrt{a^2+b^2+c^2}=|a|+|b|+|c|$ $⇒a^2+b^2+c^2=a^2+b^2+c^2+2(|a||b|+|b||c|+|c||a|)$ $⇒|a||b|+|b||c|+|c||a|=0$ $⇒ab=bc = ca=0$ ⇒ Any two of a, b, c are zero. |