Calculate the magnetic moment of a divalent ion in aqueous solution if its atomic number is 27.
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $ 3.87\text{ BM} $
For these, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the 'spin-only' formula, i.e.
$ \mu=\sqrt{n(n+2)} $
in Bohr magneton (BM)
where n is the number of unpaired electrons and
In question it is given atomic number is 27, so the divalent ion in aqueous solution will have $d^7$ configuration (3 unpaired electrons). The magnetic moment is
$ \mu=\sqrt{3(3+2)}={3.87}\text{ BM} $