Which product is formed on reaction between ethanamine and ethanoic anhydride?

A. \(CH_3CH_2NHCOCH_3\)

B. \(CH_3NHCOC_2H_5\)

C. \(CH_3COOH\)

D. \(C_2H_5COOH\)

E. \(CH_3CH_2NHCOC_2H_5\)

Choose the correct answer from the options given below:

A and C only

The correct answer is option 3. A and C only.

Let us explore the reaction between ethanamine (ethylamine) and ethanoic anhydride (acetic anhydride):

Reactants:

Ethanamine:

Chemical formula: \( CH_3CH_2NH_2 \)

It is a primary amine with an ethyl group (\( CH_3CH_2 \)) and an amino group (\( NH_2 \)).

Ethanoic Anhydride:

Chemical formula: \( (CH_3CO)_2O \)

It is an anhydride of acetic acid (ethanoic acid), consisting of two acetyl groups (\( CH_3CO \)) linked by an oxygen atom.

The reaction between ethanamine and ethanoic anhydride is an example of an acetylation reaction, where the amino group of the amine reacts with the anhydride to form an amide and a carboxylic acid.

Products:

N-Ethylacetamide: This is the main product of the reaction. The ethanamine (ethylamine) is acetylated, and the resulting compound is N-ethylacetamide, where the amino group has been acetylated to form an amide bond.

Acetic Acid: This is the by-product of the reaction. Acetic acid is formed when the acetyl group of ethanoic anhydride reacts with the amino group of the amine.

Incorrect Options:

B. \(CH_3NHCOC_2H_5\): This compound is N-Methylpropionamide, which is not the product of this reaction.

D. \(C_2H_5COOH\): This is propionic acid, not a product of the reaction with ethanoic anhydride.

E. \(CH_3CH_2NHCOC_2H_5\): This is N-Ethylpropionamide, which is not relevant to this reaction as it involves propionic anhydride, not ethanoic anhydride.

Summary:

The reaction between ethanamine and ethanoic anhydride yields:

N-Ethylacetamide (\(CH_3CH_2NHCOCH_3\))

Acetic Acid (\(CH_3COOH\))

Thus, the correct answer is option 3: A and C only, as it correctly identifies the products formed from this reaction.