Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

$\underset{θ→0+}{\lim}\frac{\sin\sqrt{θ}}{\sqrt{\sin θ}}$ is equal to

Options:

0

1

-1

none of these

Correct Answer:

1

Explanation:

Limit = $\underset{h→0}{\lim}\frac{\sin\sqrt{h}}{\sqrt{\sin h}}=\underset{h→0}{\lim}\left(\frac{\sin\sqrt{h}}{\sqrt{h}}\right)\left(\frac{1}{\sqrt{\sin h/h}}\right)=1$