Practicing Success
Practicing Success
CUET Preparation Today
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$2\begin{bmatrix}x&5\\7&y-3\end{bmatrix}+\begin{bmatrix}3&-4\\1&2\end{bmatrix}=\begin{bmatrix}7&6\\15&14\end{bmatrix}$ $⇒2\begin{bmatrix}x&5\\7&y-3\end{bmatrix}=\begin{bmatrix}4&10\\14&12\end{bmatrix}$ $⇒\begin{bmatrix}x&5\\7&y-3\end{bmatrix}=\begin{bmatrix}2&5\\7&6\end{bmatrix}$ $⇒x=2,y=9$ |
