In the given figure, if AB, DE are parallel and ∠ABC = 48°, then the value of ∠ACB + 1.5 ∠ACD is?
Answer & explanation
Correct answer: option 3
ATQ,
3a = 48°
a = 16°
Now, as per parallel line concept:
⇒ ∠ABC + ∠DCB = 180°
⇒ 3a + 2a + b = 180°
⇒ b = 180° - 80° = 100° = ∠ACB
⇒ Hence, ∠ACB + 1.5∠ACD = b + 1.5(2a) = 100° + 48° = 148°