A man travelled 91 km downstream in a river using a speedboat and then returned back. It took him 20 hours altogether. If the speed of his boat is 10 km/hr in still water, then rate of flow of water in the river is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 3 km/hr
Let speed of boat = 10 km/h
speed of river = x km/h
Downstream speed = 10 + x km/h
Upstream speed = 10 - x km/h
$Time=\frac{Distance}{Speed}$
Time downstream = $\frac{91}{10+x}$
Time upstream = $\frac{91}{10-x}$
Total time is $\frac{91}{10+x}+\frac{91}{10-x}=20$
$91(10-x)+91(10+x)=20(10-x)(10+x)$
$910-91x+910+91x=20(100-x^2)$
$91(20)=20(100-x^2)$
$91=100-x^2$
$x^2=9$
$x=3$