Three identical dice are thrown together. The probability that distinct numbers appear on them, is
Answer & explanation
Correct answer: option 2
The total number of elementary events associated to the given random experiment is $6^3$.
Three dice will show distinct numbers in ${^6C}_3 × 3!$ ways.
∴ Required probability =$\frac{^6C_3 × 3!}{6^3}=\frac{5}{9}$