Practicing Success
Practicing Success
CUET Preparation Today
The value of c in Rolle's theorem for the function $f(x)=x^3-3x$ in the interval$[0, \sqrt{3}]$ is : |
1 $±1$ $\frac{1}{3}$ $-1$ |
1 |
The correct answer is Option (1) → 1 $f(x)=x^3-3x$ $f'(x)=3x^2-3=0$ $⇒x=1$ so $c = 1$ |
