The value of c in Rolle's theorem for the function $f(x)=x^3-3x$ in the interval$[0, \sqrt{3}]$ is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 1
$f(x)=x^3-3x$
$f'(x)=3x^2-3=0$
$⇒x=1$ so $c = 1$
The value of c in Rolle's theorem for the function $f(x)=x^3-3x$ in the interval$[0, \sqrt{3}]$ is :
Correct answer: option 1
The correct answer is Option (1) → 1
$f(x)=x^3-3x$
$f'(x)=3x^2-3=0$
$⇒x=1$ so $c = 1$