Practicing Success
If the first and last terms of the geometric progression (G.P.) as given below are 3 and 36, and r = 3, then the number of terms, in the given G.P. are: |
6 5 4 3 |
6 |
The formula for the nth term in a GP: an = a1 × r(n-1) Substituting the given values: 729 = 3 × 3(n-1) 729 = 3(n) 36 = 3(n) n = 6 |