Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Nuclei

Question:

The Kα X-ray emission line of tungsten occurs at  λ = 0.021 nm. The energy difference between K and L levels in this atom is about

Options:

0.51Mev

1.2MeV

59KeV

13.6MeV

Correct Answer:

59KeV

Explanation:

$\text{Energy difference betweel K and L level is given by } \lambda_{K_{\alpha}} = \frac{hc}{E_K - E_L}$

$E_K - E_L = \frac{1240 eV}{0.021} = 59KeV$