The integrating factor of differential equation $\frac{dy}{dx}+y \, tan \, x = sec \, x $ is :

$e^{cos\, x}$ $sec\, x$ $e^{sec\, x}$ $cos\, x$

$sec\, x$

The correct answer is Option (2) → $\sec x$ $\frac{dy}{dx}+y\tan x =\sec x$ $I.F,=e^{\int\tan xdx}$ $=e^{\log|\sec x|}$ $=\sec x$